Simple way to round

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QuietBloke

TomToad

Im not at my home PC so I cant try it but what if you did the following.

f/abs(f) should give either 1 or -1
go one further and f/abs(2*f) should give 0.5 or -0.5

so I think you can do :

i = f + (f / abs(f*2))

so you will either add or subtract 0.5 from f.

(I think)

[edit]
duh !

or you can just do an if statement

Local i:Int
Local f:Float
f= -2.4

if f < 0 then
i=f-0.5
else
i=f+0.5
end if

Print i

[/edit]