Len is now a FUNCTION and not an operator

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Fabian.

BE AWARE THAT IT IS NOW DEFINATLY A FUNCTION

That's wrong.

LEN is REALLY REALLY a unitary operator

And this of course is right.

Here are three proofs:

1.: You can't find the source code or at least an extern declaration for this "function" (which you can do for all other functions)

2.: You can't find the memory address of the entry point of this "function":

Strict
Framework brl.blitz

Local LenPtr:Byte Ptr = Len
Local LenInt = Int LenPtr
WriteStdout "The Len-function is located at: " + LenInt + "~n"

3.: You don't need brackets at all:

Strict
Framework brl.blitz

WriteStdout Len "123" + 1
WriteStdout "~n"

The only need for brackets is if you're using V1.22/1.24 and want to show the compiler that the expression which is Len's parameter should be compiled before the Len-operator itself. This is because the operator just changed precedence - in V1.20 and before the precedence was lower than the member access operator and higher than the negation operator; in V1.22/1.24 in contrast it has same precedence like the New-operator (which is higher than the member access operator).