Fast InvSqrt in Max

Here's another version if anyone feels like testing it. I'm pretty sure it'll always be slower than the first version I tested but...well, just thought I'd experiment.

Instead of returning the result, you pass the result in as a float pointer

This requires a modification to the benchmarking function as well, and so I only tested this solution "alone" (too lazy to change all the other functions :).

As it is, it's about 200 ms slower for me than my first version.

Here's the code to test it

Function InvSqrtSOS2(x:Float, ret:Float Ptr)
    Local xhalf:Float = 0.5*x
	Local i:Int = $5f3759df - Int Ptr(Varptr(x))[0] Shr 1
	Local ox:Float = Float Ptr(Varptr(i))[0]

	ret[0] = ox *(1.5 - (xhalf*ox*ox))
	
End Function

Function BenchmarkInvSqrt(label:String, func(x:Float, ret:Float Ptr))

	Local ii:Int
	Local res:Float Ptr = New Float[1]
	Local startTime:Long
	Local endTime:Long
	
	startTime = MilliSecs()
	For ii=1 To 100000000
	 func(Float(ii), res)
	'Print res
	Next
	
	endTime = MilliSecs() - startTime
	Print label + ":"+ endTime

End Function


BenchmarkInvSqrt("SoS2", InvSqrtSOS2)