Millisecs() = 0

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Bill Stanbrook

For more info on this subject, check out the topic linked below, and in particular, Floyds contribution.

http://www.blitzbasic.com/Community/posts.php?topic=49285#548324

Here's some testing code I made up while I was mucking around with this.

Open in online IDE

Graphics 800, 600, 0, 2

Const MAX_POSITIVE = 2147483647
Const MAX_NEGATIVE = -2147483648

current_time = MAX_POSITIVE
deadline_time = MAX_POSITIVE + 1

;current_time = -1
;deadline_time = 0

;Print "Millisecs() wrapover occurs every " + ( ( ( ( MAX_POSITIVE / 1000.0 ) / 60.0 ) / 60.0 ) / 24.0 ) + " days."
Print 
Print "current_time = " + current_time
Print "deadline_time = " + deadline_time
Print
Print "Time remaining = " + ( deadline_time - current_time )
Print

; -- Check if 'current_time' has exceeded 'deadline_time'. This should work even if one or both times have
;~ wrapped over to negative, or if one or both times have wrapped from negative to zero or positive.
;~ Substitute '>=' for '>' when testing if 'current_time' has reached or exceeded 'deadline_time'.
If ( current_time - deadline_time ) > 0
	Print "Timeout occurred"
Else
	Print "No timeout occurred"
EndIf 
;^^^^^^

WaitKey ()

End