Global Functions not visible to Extended Types

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It really names an object instance, but you are trying to access something that is part of the class, not of an instance of the class.


That was my first explanation too, but if that's the case, why does it compile just fine if A is an integer? It's only if A is a function pointer that it fails.


Fredborg: Doh, yep, that obviously works. I have no idea why I didn't think of it. Guess I just assumed it wouldn't since super didn't. Thanks.