Only thing I can think of is there might be some compiler overhead to the array that is not present with MemAlloc
Although that might be neglibile, I suspect internally the array has to call MemAlloc as well as do the refernce counting for the array.
I dont know for sure but logic tells me Memalloc is less code generated by the compiler.
Doug Stastny
Although that might be neglibile, I suspect internally the array has to call MemAlloc as well as do the refernce counting for the array.
I dont know for sure but logic tells me Memalloc is less code generated by the compiler.
Doug Stastny