Well here is my shot at trying my idea.
Function FormatNumber:Float(num:Float,places:Int)
Local in:Int
in=Int(num*(10^places))
num=Float(in/(10^places))
Return(num)
End Function
num:Float = 3.6573468
Print FormatNumber(num,2)
Results was:
Process complete
3.65000010
Guess my idea didn't work ...
Thanks for the help...
Function FormatNumber:Float(num:Float,places:Int)
Local in:Int
in=Int(num*(10^places))
num=Float(in/(10^places))
Return(num)
End Function
num:Float = 3.6573468
Print FormatNumber(num,2)
Results was:
Process complete
3.65000010
Guess my idea didn't work ...
Thanks for the help...