Dynamic Resizing

And with this :

Type toto
	Field index:Int[][]

	Method Init(val:Int, val1:Int)
		index=index[..val+1]
		index[val]=index[val][..val1]
	End Method
End Type

' We create a new type toto
ex:toto=New toto
' We initialize first array to 0 (1 index) and second array to 0-2 (3 index)
ex.Init(0,3)
' We assign the 3 values to array [0] because there is space for 3 values in the second array
ex.index[0]=[1,2,3]  ' Assign 3 values to the first array index 0
' Print result
Print ex.index[0][0]
Print ex.index[0][1]
Print ex.index[0][2]
Print

' Now we need 5 values in the second array.
' We resize this array.
ex.Init(0,5)
' We assign value 4 and 5 (you need to assign new value one by one)
ex.index[0][3]=4 ; ex.index[0][4]=5
' Print result
Print ex.index[0][0]
Print ex.index[0][1]
Print ex.index[0][2]
Print ex.index[0][3]
Print ex.index[0][4]

You need to index the first array before init the second array.
Array[][] indicate array is created but not sized, return an error.
You can do this :
First assign an array [0][] or
First assign an array [2][] or
First assign an array [0][10] or First assign an array [2][10]
No importance since the first array is initialized.

More compact, no pointer.