It appears that the "IF"-command considers everything that isn't "0" as "True".
Try this code:
You can experiment with the value ("5" in the example code) and set it to "0" and see what it does to the IF-statement.
The CASE-command is only True if the parameter in an exact match.
As Michael said: Instr returns the position at which your string ("ABC") appears in the string you want it to search in (a$).
Therefore the IF-statement accepts this position (which isn't "0") as True, and the CASE doesn't match the TRUE parameter you've set by the SELECT statement (True = 1).
What you can do with the Select-statement:
This way the CASE-statement chechs the comparison between the value returned by "Instr" and "> 0", which is "True".
[Edit]
It seems that JazzieB had the same idea as I did and we were typing at the same time. lol
Try this code:
Open in online IDEIf 5 Then Print "IF-command sees TRUE" Else Print "IF-command sees FALSE" EndIf
You can experiment with the value ("5" in the example code) and set it to "0" and see what it does to the IF-statement.
The CASE-command is only True if the parameter in an exact match.
As Michael said: Instr returns the position at which your string ("ABC") appears in the string you want it to search in (a$).
Therefore the IF-statement accepts this position (which isn't "0") as True, and the CASE doesn't match the TRUE parameter you've set by the SELECT statement (True = 1).
What you can do with the Select-statement:
a$="AAAABBBBBBBBFFFFFFDDDDDDABCAABB" Select True Case Instr(a$,"ABC") > 0 End End Select
This way the CASE-statement chechs the comparison between the value returned by "Instr" and "> 0", which is "True".
[Edit]
It seems that JazzieB had the same idea as I did and we were typing at the same time. lol