I Hate Maths

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Ross C

soh cah toa

Mind that from school? Always helps me out.

....../..|.
....h/...|.
...5/....|.
.../.....|o
../45 deg|.
..-------'.
.....a.....

h=hyp
o=opposite
a=adjacent

for side (a) you use the 'soh' 'cah' or 'toa'

So use either toa or cah, because they both use the adjacent angle :)

we'll use cos:

cos 45= adjacent/Hyp
C A H

0.707(this number is rounded)=adjacent/5

we take the 5 over to the other side, by multiplying the whole equation by 5

0.707*5=adjacent

so

adjacent=3.5

Then use pytharoris theorum(sp??)

basically the square of the opposite and the the square of the adjacent, when added, then take the square root to find the hyp.

hyp2=adjacent2+opposite2

where 2 means squared.

so:

opposite2=hyp2-adjacent2
opposite2=25-12.25
opposite2=12.75
opposite=sqr root of 12.75
opposite=3.57

whessssshh. Hope you followed some of that :S

for your problem just take out my hyp value, and stick in your own and your own angle and follow it thru. good luck!