Rotating a gradient

BlitzPlus Forums/BlitzPlus Programming/Rotating a gradient

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MutteringGoblin
 #1
This might work.

xr# = (xg# * Cos(a#)) - (yg# * Sin(a#))
xr# = (yg# * Cos(a#)) + (xg# * Sin(a#))


Where a# is the angle of rotation.

I'm not very good at trigonometry but that's apparently the formula to rotate a point, and I'm guessing a point is the same as a gradient.