With your coords from your first post, I have found the equidistant point for the three vertices, using my program above. They are as follows:
x: 7.92265
y: -12.0732
z: 25.2974
Run this piece of code to see that the three distances are equal:
x: 7.92265
y: -12.0732
z: 25.2974
Run this piece of code to see that the three distances are equal:
Open in online IDE;triangle coords ;-3.1x,-19.2y,14.9z ;21.2x,-8.9y,15.6z ;-1.1x,-12.4y,39.4z ;circumcenter coords x#=7.92265 y#=-12.0732 z#=25.2974 dx#=(-3.1-x) dy#=(-19.2-y) dz#=(14.9-z) dist1#=Sqr(dx*dx+dy*dy+dz*dz) dx#=(21.2-x) dy#=(-8.9-y) dz#=(15.6-z) dist2#=Sqr(dx*dx+dy*dy+dz*dz) dx#=(-1.1-x) dy#=(-12.4-y) dz#=(39.4-z) dist3#=Sqr(dx*dx+dy*dy+dz*dz) Print dist1 Print dist2 Print dist3 ;all distances are equal MouseWait